Java中除数为0时计算报错的问题
在数学中,规定被除数不能为0
那么在Java程序中一旦出现除数为0时,会出现什么情况呢:
对于除数a和被除数b (b=0),
(1)如果二者均为int型(long也算是int型),结果会抛出异常:java.lang.ArithmeticException: / by zero
(2)如果其中有一个为double或者float型,结果则是Infinity
另外,对于Double和Float的NaN/Infinity等是否相等呢:
Float.NaN == Double.NaN
false
Float.NEGATIVE_INFINITY == Double.NEGATIVE_INFINITY
true
Float.POSITIVE_INFINITY == Double.POSITIVE_INFINITY
true
代码如下:
public class DivideZeroTest { public static void main(String[] args) { float f1 = 1; double d1 = 1; int i1 = 1; int i0 = 0; double f0 = 0; double d0 = 0; try { System.out.println(i1 / i0); } catch (Exception e) { System.out.println(e); } System.out.println(i1 / f0); System.out.println(i1 / d0); System.out.println(f1 / i0); System.out.println(f1 / f0); System.out.println(f1 / d0); System.out.println(d1 / i0); System.out.println(d1 / f0); System.out.println(d1 / d0); System.out.println(Float.NaN == Double.NaN); System.out.println(Float.NEGATIVE_INFINITY == Double.NEGATIVE_INFINITY); System.out.println(Float.POSITIVE_INFINITY == Double.POSITIVE_INFINITY); } }